1975 Calder Cup Playoffs

The 1975 Calder Cup Playoffs of the American Hockey League began on April 2, 1975. The eight teams that qualified played best-of-7 series for Division Semifinals and Finals. The division champions played a best-of-7 series for the Calder Cup. The Calder Cup Final ended on May 7, 1975 with the Springfield Indians defeating the New Haven Nighthawks four games to one to win the Calder Cup for the fourth time in team history.

Playoff seeds
After the 1974–75 AHL regular season, the top three teams from each division qualified for the playoffs. The Providence Reds finished the regular season with the best overall record.

Northern Division

 * 1) Providence Reds - 98 points
 * 2) Rochester Americans - 93 points
 * 3) Nova Scotia Voyageurs - 89 points
 * 4) Springfield Indians - 78 points
 * 5) New Haven Nighthawks - 71 points (Played in the South division part of the bracket after beating Syracuse in a one game playoff.)

Southern Division

 * 1) Virginia Wings - 75 points
 * 2) Richmond Robins - 65 points
 * 3) Hershey Bears - 64 points

Bracket
In each round, the higher seed receives home ice advantage, meaning they receive the "extra" game on home-ice if the series reaches the maximum number of games. There is no set series format due to arena scheduling conflicts and travel considerations.

Division Semifinals

 * Note: Home team is listed first.