1990 Calder Cup Playoffs

The 1990 Calder Cup Playoffs of the American Hockey League began on April 4, 1990. The eight teams that qualified, four from each division, played best-of-7 series for Division Semifinals and Division Finals. The division champions played a best-of-7 series for the Calder Cup. The Calder Cup Final ended on May 18, 1990 with the Springfield Indians defeating the Rochester Americans four games to two to win the Calder Cup for the sixth time in team history. Despite an injury preventing him from playing in the final game, Springfield goaltender Jeff Hackett won the Jack A. Butterfield Trophy as the MVP of the playoffs.

The league instituted trophies for division champions in the playoffs; the Richard F. Canning Trophy in the North Division, and the Robert W. Clarke Trophy in the South Division.

Playoff seeds
After the 1989-90 AHL regular season, the top four teams from each division qualified for the playoffs. The Sherbrooke Canadiens finished the regular season with the best overall record for the second straight season.

Northern Division

 * 1) Sherbrooke Canadiens - 102 points
 * 2) Cape Breton Oilers - 85 points
 * 3) Springfield Indians - 80 points
 * 4) Halifax Citadels - 80 points

Southern Division

 * 1) Rochester Americans - 95 points
 * 2) Adirondack Red Wings - 95 points
 * 3) Baltimore Skipjacks - 93 points
 * 4) Utica Devils - 92 points

Bracket
In each round, the team that earned more points during the regular season receives home ice advantage, meaning they receive the "extra" game on home-ice if the series reaches the maximum number of games. There is no set series format due to arena scheduling conflicts and travel considerations.

Division Semifinals

 * Note: Home team is listed first.